3.3.1 \(\int (a g+b g x)^4 (A+B \log (\frac {e (c+d x)^2}{(a+b x)^2})) \, dx\) [201]

3.3.1.1 Optimal result
3.3.1.2 Mathematica [A] (verified)
3.3.1.3 Rubi [A] (verified)
3.3.1.4 Maple [A] (verified)
3.3.1.5 Fricas [B] (verification not implemented)
3.3.1.6 Sympy [B] (verification not implemented)
3.3.1.7 Maxima [B] (verification not implemented)
3.3.1.8 Giac [B] (verification not implemented)
3.3.1.9 Mupad [B] (verification not implemented)

3.3.1.1 Optimal result

Integrand size = 32, antiderivative size = 182 \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )\right ) \, dx=-\frac {2 B (b c-a d)^4 g^4 x}{5 d^4}+\frac {B (b c-a d)^3 g^4 (a+b x)^2}{5 b d^3}-\frac {2 B (b c-a d)^2 g^4 (a+b x)^3}{15 b d^2}+\frac {B (b c-a d) g^4 (a+b x)^4}{10 b d}+\frac {2 B (b c-a d)^5 g^4 \log (c+d x)}{5 b d^5}+\frac {g^4 (a+b x)^5 \left (A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )\right )}{5 b} \]

output
-2/5*B*(-a*d+b*c)^4*g^4*x/d^4+1/5*B*(-a*d+b*c)^3*g^4*(b*x+a)^2/b/d^3-2/15* 
B*(-a*d+b*c)^2*g^4*(b*x+a)^3/b/d^2+1/10*B*(-a*d+b*c)*g^4*(b*x+a)^4/b/d+2/5 
*B*(-a*d+b*c)^5*g^4*ln(d*x+c)/b/d^5+1/5*g^4*(b*x+a)^5*(A+B*ln(e*(d*x+c)^2/ 
(b*x+a)^2))/b
 
3.3.1.2 Mathematica [A] (verified)

Time = 0.06 (sec) , antiderivative size = 144, normalized size of antiderivative = 0.79 \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )\right ) \, dx=\frac {g^4 \left (-\frac {B (-b c+a d) \left (-12 b d (b c-a d)^3 x+6 d^2 (b c-a d)^2 (a+b x)^2+4 d^3 (-b c+a d) (a+b x)^3+3 d^4 (a+b x)^4+12 (b c-a d)^4 \log (c+d x)\right )}{6 d^5}+(a+b x)^5 \left (A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )\right )\right )}{5 b} \]

input
Integrate[(a*g + b*g*x)^4*(A + B*Log[(e*(c + d*x)^2)/(a + b*x)^2]),x]
 
output
(g^4*(-1/6*(B*(-(b*c) + a*d)*(-12*b*d*(b*c - a*d)^3*x + 6*d^2*(b*c - a*d)^ 
2*(a + b*x)^2 + 4*d^3*(-(b*c) + a*d)*(a + b*x)^3 + 3*d^4*(a + b*x)^4 + 12* 
(b*c - a*d)^4*Log[c + d*x]))/d^5 + (a + b*x)^5*(A + B*Log[(e*(c + d*x)^2)/ 
(a + b*x)^2])))/(5*b)
 
3.3.1.3 Rubi [A] (verified)

Time = 0.30 (sec) , antiderivative size = 156, normalized size of antiderivative = 0.86, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {2948, 27, 49, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (a g+b g x)^4 \left (B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )+A\right ) \, dx\)

\(\Big \downarrow \) 2948

\(\displaystyle \frac {2 B (b c-a d) \int \frac {g^5 (a+b x)^4}{c+d x}dx}{5 b g}+\frac {g^4 (a+b x)^5 \left (B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )+A\right )}{5 b}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {2 B g^4 (b c-a d) \int \frac {(a+b x)^4}{c+d x}dx}{5 b}+\frac {g^4 (a+b x)^5 \left (B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )+A\right )}{5 b}\)

\(\Big \downarrow \) 49

\(\displaystyle \frac {2 B g^4 (b c-a d) \int \left (\frac {(a d-b c)^4}{d^4 (c+d x)}-\frac {b (b c-a d)^3}{d^4}+\frac {b (a+b x)^3}{d}-\frac {b (b c-a d) (a+b x)^2}{d^2}+\frac {b (b c-a d)^2 (a+b x)}{d^3}\right )dx}{5 b}+\frac {g^4 (a+b x)^5 \left (B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )+A\right )}{5 b}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {g^4 (a+b x)^5 \left (B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )+A\right )}{5 b}+\frac {2 B g^4 (b c-a d) \left (\frac {(b c-a d)^4 \log (c+d x)}{d^5}-\frac {b x (b c-a d)^3}{d^4}+\frac {(a+b x)^2 (b c-a d)^2}{2 d^3}-\frac {(a+b x)^3 (b c-a d)}{3 d^2}+\frac {(a+b x)^4}{4 d}\right )}{5 b}\)

input
Int[(a*g + b*g*x)^4*(A + B*Log[(e*(c + d*x)^2)/(a + b*x)^2]),x]
 
output
(2*B*(b*c - a*d)*g^4*(-((b*(b*c - a*d)^3*x)/d^4) + ((b*c - a*d)^2*(a + b*x 
)^2)/(2*d^3) - ((b*c - a*d)*(a + b*x)^3)/(3*d^2) + (a + b*x)^4/(4*d) + ((b 
*c - a*d)^4*Log[c + d*x])/d^5))/(5*b) + (g^4*(a + b*x)^5*(A + B*Log[(e*(c 
+ d*x)^2)/(a + b*x)^2]))/(5*b)
 

3.3.1.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 49
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int 
[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d}, x] 
&& IGtQ[m, 0] && IGtQ[m + n + 2, 0]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 2948
Int[((A_.) + Log[(e_.)*((a_.) + (b_.)*(x_))^(n_.)*((c_.) + (d_.)*(x_))^(mn_ 
)]*(B_.))*((f_.) + (g_.)*(x_))^(m_.), x_Symbol] :> Simp[(f + g*x)^(m + 1)*( 
(A + B*Log[e*((a + b*x)^n/(c + d*x)^n)])/(g*(m + 1))), x] - Simp[B*n*((b*c 
- a*d)/(g*(m + 1)))   Int[(f + g*x)^(m + 1)/((a + b*x)*(c + d*x)), x], x] / 
; FreeQ[{a, b, c, d, e, f, g, A, B, m, n}, x] && EqQ[n + mn, 0] && NeQ[b*c 
- a*d, 0] && NeQ[m, -1] &&  !(EqQ[m, -2] && IntegerQ[n])
 
3.3.1.4 Maple [A] (verified)

Time = 1.29 (sec) , antiderivative size = 296, normalized size of antiderivative = 1.63

method result size
derivativedivides \(-\frac {-\frac {g^{4} A \left (b x +a \right )^{5}}{5}+g^{4} B \left (-\frac {\left (b x +a \right )^{5} \ln \left (\frac {e \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )^{2}}{b^{2}}\right )}{5}-\left (-\frac {2 a d}{5}+\frac {2 c b}{5}\right ) \left (\frac {\left (-a^{4} d^{4}+4 a^{3} b c \,d^{3}-6 a^{2} b^{2} c^{2} d^{2}+4 a \,b^{3} c^{3} d -b^{4} c^{4}\right ) \ln \left (\frac {1}{b x +a}\right )}{d^{5}}+\frac {\left (b x +a \right )^{4}}{4 d}-\frac {\left (-a d +c b \right ) \left (b x +a \right )^{3}}{3 d^{2}}-\frac {\left (-a^{3} d^{3}+3 a^{2} b c \,d^{2}-3 a \,b^{2} c^{2} d +b^{3} c^{3}\right ) \left (b x +a \right )}{d^{4}}-\frac {\left (-a^{2} d^{2}+2 a b c d -b^{2} c^{2}\right ) \left (b x +a \right )^{2}}{2 d^{3}}+\frac {\left (a d -c b \right )^{4} \ln \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )}{d^{5}}\right )\right )}{b}\) \(296\)
default \(-\frac {-\frac {g^{4} A \left (b x +a \right )^{5}}{5}+g^{4} B \left (-\frac {\left (b x +a \right )^{5} \ln \left (\frac {e \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )^{2}}{b^{2}}\right )}{5}-\left (-\frac {2 a d}{5}+\frac {2 c b}{5}\right ) \left (\frac {\left (-a^{4} d^{4}+4 a^{3} b c \,d^{3}-6 a^{2} b^{2} c^{2} d^{2}+4 a \,b^{3} c^{3} d -b^{4} c^{4}\right ) \ln \left (\frac {1}{b x +a}\right )}{d^{5}}+\frac {\left (b x +a \right )^{4}}{4 d}-\frac {\left (-a d +c b \right ) \left (b x +a \right )^{3}}{3 d^{2}}-\frac {\left (-a^{3} d^{3}+3 a^{2} b c \,d^{2}-3 a \,b^{2} c^{2} d +b^{3} c^{3}\right ) \left (b x +a \right )}{d^{4}}-\frac {\left (-a^{2} d^{2}+2 a b c d -b^{2} c^{2}\right ) \left (b x +a \right )^{2}}{2 d^{3}}+\frac {\left (a d -c b \right )^{4} \ln \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )}{d^{5}}\right )\right )}{b}\) \(296\)
parts \(\frac {g^{4} A \left (b x +a \right )^{5}}{5 b}-\frac {g^{4} B \left (-\frac {\left (b x +a \right )^{5} \ln \left (\frac {e \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )^{2}}{b^{2}}\right )}{5}-\left (-\frac {2 a d}{5}+\frac {2 c b}{5}\right ) \left (\frac {\left (-a^{4} d^{4}+4 a^{3} b c \,d^{3}-6 a^{2} b^{2} c^{2} d^{2}+4 a \,b^{3} c^{3} d -b^{4} c^{4}\right ) \ln \left (\frac {1}{b x +a}\right )}{d^{5}}+\frac {\left (b x +a \right )^{4}}{4 d}-\frac {\left (-a d +c b \right ) \left (b x +a \right )^{3}}{3 d^{2}}-\frac {\left (-a^{3} d^{3}+3 a^{2} b c \,d^{2}-3 a \,b^{2} c^{2} d +b^{3} c^{3}\right ) \left (b x +a \right )}{d^{4}}-\frac {\left (-a^{2} d^{2}+2 a b c d -b^{2} c^{2}\right ) \left (b x +a \right )^{2}}{2 d^{3}}+\frac {\left (a d -c b \right )^{4} \ln \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )}{d^{5}}\right )\right )}{b}\) \(298\)
risch \(\frac {4 g^{4} b^{2} B \ln \left (d x +c \right ) a^{2} c^{3}}{d^{3}}-\frac {2 g^{4} b^{3} B \ln \left (d x +c \right ) a \,c^{4}}{d^{4}}-\frac {g^{4} b^{3} B a \,x^{4}}{10}-\frac {8 g^{4} B \,a^{4} x}{5}-\frac {2 g^{4} B \ln \left (d x +c \right ) a^{5}}{5 b}-\frac {g^{4} b^{3} B a \,c^{2} x^{2}}{d^{2}}+\frac {4 g^{4} b B \,a^{3} c x}{d}-\frac {4 g^{4} b^{2} B \,a^{2} c^{2} x}{d^{2}}+\frac {2 g^{4} b^{3} B a \,c^{3} x}{d^{3}}-\frac {4 g^{4} b B \ln \left (d x +c \right ) a^{3} c^{2}}{d^{2}}+\frac {g^{4} b^{4} A \,x^{5}}{5}+\frac {2 g^{4} b^{3} B a c \,x^{3}}{3 d}+\frac {2 g^{4} b^{2} B \,a^{2} c \,x^{2}}{d}+2 g^{4} b^{2} A \,a^{2} x^{3}-\frac {8 g^{4} b^{2} B \,a^{2} x^{3}}{15}-\frac {2 g^{4} b^{4} B \,c^{2} x^{3}}{15 d^{2}}+2 g^{4} b A \,a^{3} x^{2}+\frac {\left (b x +a \right )^{5} g^{4} B \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right )}{5 b}+\frac {2 g^{4} B \ln \left (d x +c \right ) a^{4} c}{d}+\frac {2 g^{4} b^{4} B \ln \left (d x +c \right ) c^{5}}{5 d^{5}}-\frac {2 g^{4} b^{4} B \,c^{4} x}{5 d^{4}}-\frac {6 g^{4} b B \,a^{3} x^{2}}{5}+\frac {g^{4} b^{4} B \,c^{3} x^{2}}{5 d^{3}}+g^{4} A \,a^{4} x +g^{4} b^{3} A a \,x^{4}+\frac {g^{4} b^{4} B c \,x^{4}}{10 d}\) \(447\)
parallelrisch \(\frac {120 B x \,a^{3} b^{2} c \,d^{4} g^{4}-120 B x \,a^{2} b^{3} c^{2} d^{3} g^{4}+60 B x a \,b^{4} c^{3} d^{2} g^{4}+60 B \ln \left (b x +a \right ) a^{4} b c \,d^{4} g^{4}-120 B \ln \left (b x +a \right ) a^{3} b^{2} c^{2} d^{3} g^{4}+120 B \ln \left (b x +a \right ) a^{2} b^{3} c^{3} d^{2} g^{4}-60 B \ln \left (b x +a \right ) a \,b^{4} c^{4} d \,g^{4}+6 B \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) b^{5} c^{5} g^{4}-12 B x \,b^{5} c^{4} d \,g^{4}+30 A \,x^{4} a \,b^{4} d^{5} g^{4}-3 B \,x^{4} a \,b^{4} d^{5} g^{4}+3 B \,x^{4} b^{5} c \,d^{4} g^{4}+60 A \,x^{3} a^{2} b^{3} d^{5} g^{4}-16 B \,x^{3} a^{2} b^{3} d^{5} g^{4}+30 B \,x^{4} \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a \,b^{4} d^{5} g^{4}+60 B \,x^{3} \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a^{2} b^{3} d^{5} g^{4}+60 B \,x^{2} \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a^{3} b^{2} d^{5} g^{4}+12 B \,b^{5} g^{4} c^{5}-36 B \,a^{4} b c \,d^{4} g^{4}-60 B \,a^{3} b^{2} c^{2} d^{3} g^{4}+90 B \,a^{2} b^{3} c^{3} d^{2} g^{4}-54 B a \,b^{4} c^{4} d \,g^{4}+6 B \,x^{5} \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) b^{5} d^{5} g^{4}-4 B \,x^{3} b^{5} c^{2} d^{3} g^{4}+60 A \,x^{2} a^{3} b^{2} d^{5} g^{4}-36 B \,x^{2} a^{3} b^{2} d^{5} g^{4}+6 B \,x^{2} b^{5} c^{3} d^{2} g^{4}+30 A x \,a^{4} b \,d^{5} g^{4}-48 B x \,a^{4} b \,d^{5} g^{4}+48 B \,a^{5} d^{5} g^{4}-60 B \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a^{3} b^{2} c^{2} d^{3} g^{4}-30 B \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a \,b^{4} c^{4} d \,g^{4}+30 B x \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a^{4} b \,d^{5} g^{4}+20 B \,x^{3} a \,b^{4} c \,d^{4} g^{4}+60 B \,x^{2} a^{2} b^{3} c \,d^{4} g^{4}-30 B \,x^{2} a \,b^{4} c^{2} d^{3} g^{4}+60 B \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a^{2} b^{3} c^{3} d^{2} g^{4}+30 B \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a^{4} b c \,d^{4} g^{4}-90 A \,a^{4} b c \,d^{4} g^{4}-30 A \,a^{5} d^{5} g^{4}+6 A \,x^{5} b^{5} d^{5} g^{4}-12 B \ln \left (b x +a \right ) a^{5} d^{5} g^{4}+12 B \ln \left (b x +a \right ) b^{5} c^{5} g^{4}}{30 d^{5} b}\) \(896\)

input
int((b*g*x+a*g)^4*(A+B*ln(e*(d*x+c)^2/(b*x+a)^2)),x,method=_RETURNVERBOSE)
 
output
-1/b*(-1/5*g^4*A*(b*x+a)^5+g^4*B*(-1/5*(b*x+a)^5*ln(e*(a*d/(b*x+a)-b*c/(b* 
x+a)-d)^2/b^2)-(-2/5*a*d+2/5*c*b)*(1/d^5*(-a^4*d^4+4*a^3*b*c*d^3-6*a^2*b^2 
*c^2*d^2+4*a*b^3*c^3*d-b^4*c^4)*ln(1/(b*x+a))+1/4/d*(b*x+a)^4-1/3*(-a*d+b* 
c)/d^2*(b*x+a)^3-(-a^3*d^3+3*a^2*b*c*d^2-3*a*b^2*c^2*d+b^3*c^3)/d^4*(b*x+a 
)-1/2*(-a^2*d^2+2*a*b*c*d-b^2*c^2)/d^3*(b*x+a)^2+1/d^5*(a*d-b*c)^4*ln(a*d/ 
(b*x+a)-b*c/(b*x+a)-d))))
 
3.3.1.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 457 vs. \(2 (170) = 340\).

Time = 0.30 (sec) , antiderivative size = 457, normalized size of antiderivative = 2.51 \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )\right ) \, dx=\frac {6 \, A b^{5} d^{5} g^{4} x^{5} - 12 \, B a^{5} d^{5} g^{4} \log \left (b x + a\right ) + 3 \, {\left (B b^{5} c d^{4} + {\left (10 \, A - B\right )} a b^{4} d^{5}\right )} g^{4} x^{4} - 4 \, {\left (B b^{5} c^{2} d^{3} - 5 \, B a b^{4} c d^{4} - {\left (15 \, A - 4 \, B\right )} a^{2} b^{3} d^{5}\right )} g^{4} x^{3} + 6 \, {\left (B b^{5} c^{3} d^{2} - 5 \, B a b^{4} c^{2} d^{3} + 10 \, B a^{2} b^{3} c d^{4} + 2 \, {\left (5 \, A - 3 \, B\right )} a^{3} b^{2} d^{5}\right )} g^{4} x^{2} - 6 \, {\left (2 \, B b^{5} c^{4} d - 10 \, B a b^{4} c^{3} d^{2} + 20 \, B a^{2} b^{3} c^{2} d^{3} - 20 \, B a^{3} b^{2} c d^{4} - {\left (5 \, A - 8 \, B\right )} a^{4} b d^{5}\right )} g^{4} x + 12 \, {\left (B b^{5} c^{5} - 5 \, B a b^{4} c^{4} d + 10 \, B a^{2} b^{3} c^{3} d^{2} - 10 \, B a^{3} b^{2} c^{2} d^{3} + 5 \, B a^{4} b c d^{4}\right )} g^{4} \log \left (d x + c\right ) + 6 \, {\left (B b^{5} d^{5} g^{4} x^{5} + 5 \, B a b^{4} d^{5} g^{4} x^{4} + 10 \, B a^{2} b^{3} d^{5} g^{4} x^{3} + 10 \, B a^{3} b^{2} d^{5} g^{4} x^{2} + 5 \, B a^{4} b d^{5} g^{4} x\right )} \log \left (\frac {d^{2} e x^{2} + 2 \, c d e x + c^{2} e}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right )}{30 \, b d^{5}} \]

input
integrate((b*g*x+a*g)^4*(A+B*log(e*(d*x+c)^2/(b*x+a)^2)),x, algorithm="fri 
cas")
 
output
1/30*(6*A*b^5*d^5*g^4*x^5 - 12*B*a^5*d^5*g^4*log(b*x + a) + 3*(B*b^5*c*d^4 
 + (10*A - B)*a*b^4*d^5)*g^4*x^4 - 4*(B*b^5*c^2*d^3 - 5*B*a*b^4*c*d^4 - (1 
5*A - 4*B)*a^2*b^3*d^5)*g^4*x^3 + 6*(B*b^5*c^3*d^2 - 5*B*a*b^4*c^2*d^3 + 1 
0*B*a^2*b^3*c*d^4 + 2*(5*A - 3*B)*a^3*b^2*d^5)*g^4*x^2 - 6*(2*B*b^5*c^4*d 
- 10*B*a*b^4*c^3*d^2 + 20*B*a^2*b^3*c^2*d^3 - 20*B*a^3*b^2*c*d^4 - (5*A - 
8*B)*a^4*b*d^5)*g^4*x + 12*(B*b^5*c^5 - 5*B*a*b^4*c^4*d + 10*B*a^2*b^3*c^3 
*d^2 - 10*B*a^3*b^2*c^2*d^3 + 5*B*a^4*b*c*d^4)*g^4*log(d*x + c) + 6*(B*b^5 
*d^5*g^4*x^5 + 5*B*a*b^4*d^5*g^4*x^4 + 10*B*a^2*b^3*d^5*g^4*x^3 + 10*B*a^3 
*b^2*d^5*g^4*x^2 + 5*B*a^4*b*d^5*g^4*x)*log((d^2*e*x^2 + 2*c*d*e*x + c^2*e 
)/(b^2*x^2 + 2*a*b*x + a^2)))/(b*d^5)
 
3.3.1.6 Sympy [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 998 vs. \(2 (163) = 326\).

Time = 4.02 (sec) , antiderivative size = 998, normalized size of antiderivative = 5.48 \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )\right ) \, dx=\frac {A b^{4} g^{4} x^{5}}{5} - \frac {2 B a^{5} g^{4} \log {\left (x + \frac {\frac {2 B a^{6} d^{5} g^{4}}{b} + 10 B a^{5} c d^{4} g^{4} - 20 B a^{4} b c^{2} d^{3} g^{4} + 20 B a^{3} b^{2} c^{3} d^{2} g^{4} - 10 B a^{2} b^{3} c^{4} d g^{4} + 2 B a b^{4} c^{5} g^{4}}{2 B a^{5} d^{5} g^{4} + 10 B a^{4} b c d^{4} g^{4} - 20 B a^{3} b^{2} c^{2} d^{3} g^{4} + 20 B a^{2} b^{3} c^{3} d^{2} g^{4} - 10 B a b^{4} c^{4} d g^{4} + 2 B b^{5} c^{5} g^{4}} \right )}}{5 b} + \frac {2 B c g^{4} \cdot \left (5 a^{4} d^{4} - 10 a^{3} b c d^{3} + 10 a^{2} b^{2} c^{2} d^{2} - 5 a b^{3} c^{3} d + b^{4} c^{4}\right ) \log {\left (x + \frac {12 B a^{5} c d^{4} g^{4} - 20 B a^{4} b c^{2} d^{3} g^{4} + 20 B a^{3} b^{2} c^{3} d^{2} g^{4} - 10 B a^{2} b^{3} c^{4} d g^{4} + 2 B a b^{4} c^{5} g^{4} - 2 B a c g^{4} \cdot \left (5 a^{4} d^{4} - 10 a^{3} b c d^{3} + 10 a^{2} b^{2} c^{2} d^{2} - 5 a b^{3} c^{3} d + b^{4} c^{4}\right ) + \frac {2 B b c^{2} g^{4} \cdot \left (5 a^{4} d^{4} - 10 a^{3} b c d^{3} + 10 a^{2} b^{2} c^{2} d^{2} - 5 a b^{3} c^{3} d + b^{4} c^{4}\right )}{d}}{2 B a^{5} d^{5} g^{4} + 10 B a^{4} b c d^{4} g^{4} - 20 B a^{3} b^{2} c^{2} d^{3} g^{4} + 20 B a^{2} b^{3} c^{3} d^{2} g^{4} - 10 B a b^{4} c^{4} d g^{4} + 2 B b^{5} c^{5} g^{4}} \right )}}{5 d^{5}} + x^{4} \left (A a b^{3} g^{4} - \frac {B a b^{3} g^{4}}{10} + \frac {B b^{4} c g^{4}}{10 d}\right ) + x^{3} \cdot \left (2 A a^{2} b^{2} g^{4} - \frac {8 B a^{2} b^{2} g^{4}}{15} + \frac {2 B a b^{3} c g^{4}}{3 d} - \frac {2 B b^{4} c^{2} g^{4}}{15 d^{2}}\right ) + x^{2} \cdot \left (2 A a^{3} b g^{4} - \frac {6 B a^{3} b g^{4}}{5} + \frac {2 B a^{2} b^{2} c g^{4}}{d} - \frac {B a b^{3} c^{2} g^{4}}{d^{2}} + \frac {B b^{4} c^{3} g^{4}}{5 d^{3}}\right ) + x \left (A a^{4} g^{4} - \frac {8 B a^{4} g^{4}}{5} + \frac {4 B a^{3} b c g^{4}}{d} - \frac {4 B a^{2} b^{2} c^{2} g^{4}}{d^{2}} + \frac {2 B a b^{3} c^{3} g^{4}}{d^{3}} - \frac {2 B b^{4} c^{4} g^{4}}{5 d^{4}}\right ) + \left (B a^{4} g^{4} x + 2 B a^{3} b g^{4} x^{2} + 2 B a^{2} b^{2} g^{4} x^{3} + B a b^{3} g^{4} x^{4} + \frac {B b^{4} g^{4} x^{5}}{5}\right ) \log {\left (\frac {e \left (c + d x\right )^{2}}{\left (a + b x\right )^{2}} \right )} \]

input
integrate((b*g*x+a*g)**4*(A+B*ln(e*(d*x+c)**2/(b*x+a)**2)),x)
 
output
A*b**4*g**4*x**5/5 - 2*B*a**5*g**4*log(x + (2*B*a**6*d**5*g**4/b + 10*B*a* 
*5*c*d**4*g**4 - 20*B*a**4*b*c**2*d**3*g**4 + 20*B*a**3*b**2*c**3*d**2*g** 
4 - 10*B*a**2*b**3*c**4*d*g**4 + 2*B*a*b**4*c**5*g**4)/(2*B*a**5*d**5*g**4 
 + 10*B*a**4*b*c*d**4*g**4 - 20*B*a**3*b**2*c**2*d**3*g**4 + 20*B*a**2*b** 
3*c**3*d**2*g**4 - 10*B*a*b**4*c**4*d*g**4 + 2*B*b**5*c**5*g**4))/(5*b) + 
2*B*c*g**4*(5*a**4*d**4 - 10*a**3*b*c*d**3 + 10*a**2*b**2*c**2*d**2 - 5*a* 
b**3*c**3*d + b**4*c**4)*log(x + (12*B*a**5*c*d**4*g**4 - 20*B*a**4*b*c**2 
*d**3*g**4 + 20*B*a**3*b**2*c**3*d**2*g**4 - 10*B*a**2*b**3*c**4*d*g**4 + 
2*B*a*b**4*c**5*g**4 - 2*B*a*c*g**4*(5*a**4*d**4 - 10*a**3*b*c*d**3 + 10*a 
**2*b**2*c**2*d**2 - 5*a*b**3*c**3*d + b**4*c**4) + 2*B*b*c**2*g**4*(5*a** 
4*d**4 - 10*a**3*b*c*d**3 + 10*a**2*b**2*c**2*d**2 - 5*a*b**3*c**3*d + b** 
4*c**4)/d)/(2*B*a**5*d**5*g**4 + 10*B*a**4*b*c*d**4*g**4 - 20*B*a**3*b**2* 
c**2*d**3*g**4 + 20*B*a**2*b**3*c**3*d**2*g**4 - 10*B*a*b**4*c**4*d*g**4 + 
 2*B*b**5*c**5*g**4))/(5*d**5) + x**4*(A*a*b**3*g**4 - B*a*b**3*g**4/10 + 
B*b**4*c*g**4/(10*d)) + x**3*(2*A*a**2*b**2*g**4 - 8*B*a**2*b**2*g**4/15 + 
 2*B*a*b**3*c*g**4/(3*d) - 2*B*b**4*c**2*g**4/(15*d**2)) + x**2*(2*A*a**3* 
b*g**4 - 6*B*a**3*b*g**4/5 + 2*B*a**2*b**2*c*g**4/d - B*a*b**3*c**2*g**4/d 
**2 + B*b**4*c**3*g**4/(5*d**3)) + x*(A*a**4*g**4 - 8*B*a**4*g**4/5 + 4*B* 
a**3*b*c*g**4/d - 4*B*a**2*b**2*c**2*g**4/d**2 + 2*B*a*b**3*c**3*g**4/d**3 
 - 2*B*b**4*c**4*g**4/(5*d**4)) + (B*a**4*g**4*x + 2*B*a**3*b*g**4*x**2...
 
3.3.1.7 Maxima [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 882 vs. \(2 (170) = 340\).

Time = 0.24 (sec) , antiderivative size = 882, normalized size of antiderivative = 4.85 \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )\right ) \, dx=\frac {1}{5} \, A b^{4} g^{4} x^{5} + A a b^{3} g^{4} x^{4} + 2 \, A a^{2} b^{2} g^{4} x^{3} + 2 \, A a^{3} b g^{4} x^{2} + {\left (x \log \left (\frac {d^{2} e x^{2}}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {2 \, c d e x}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {c^{2} e}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right ) - \frac {2 \, a \log \left (b x + a\right )}{b} + \frac {2 \, c \log \left (d x + c\right )}{d}\right )} B a^{4} g^{4} + 2 \, {\left (x^{2} \log \left (\frac {d^{2} e x^{2}}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {2 \, c d e x}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {c^{2} e}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right ) + \frac {2 \, a^{2} \log \left (b x + a\right )}{b^{2}} - \frac {2 \, c^{2} \log \left (d x + c\right )}{d^{2}} + \frac {2 \, {\left (b c - a d\right )} x}{b d}\right )} B a^{3} b g^{4} + 2 \, {\left (x^{3} \log \left (\frac {d^{2} e x^{2}}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {2 \, c d e x}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {c^{2} e}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right ) - \frac {2 \, a^{3} \log \left (b x + a\right )}{b^{3}} + \frac {2 \, c^{3} \log \left (d x + c\right )}{d^{3}} + \frac {{\left (b^{2} c d - a b d^{2}\right )} x^{2} - 2 \, {\left (b^{2} c^{2} - a^{2} d^{2}\right )} x}{b^{2} d^{2}}\right )} B a^{2} b^{2} g^{4} + \frac {1}{3} \, {\left (3 \, x^{4} \log \left (\frac {d^{2} e x^{2}}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {2 \, c d e x}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {c^{2} e}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right ) + \frac {6 \, a^{4} \log \left (b x + a\right )}{b^{4}} - \frac {6 \, c^{4} \log \left (d x + c\right )}{d^{4}} + \frac {2 \, {\left (b^{3} c d^{2} - a b^{2} d^{3}\right )} x^{3} - 3 \, {\left (b^{3} c^{2} d - a^{2} b d^{3}\right )} x^{2} + 6 \, {\left (b^{3} c^{3} - a^{3} d^{3}\right )} x}{b^{3} d^{3}}\right )} B a b^{3} g^{4} + \frac {1}{30} \, {\left (6 \, x^{5} \log \left (\frac {d^{2} e x^{2}}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {2 \, c d e x}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {c^{2} e}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right ) - \frac {12 \, a^{5} \log \left (b x + a\right )}{b^{5}} + \frac {12 \, c^{5} \log \left (d x + c\right )}{d^{5}} + \frac {3 \, {\left (b^{4} c d^{3} - a b^{3} d^{4}\right )} x^{4} - 4 \, {\left (b^{4} c^{2} d^{2} - a^{2} b^{2} d^{4}\right )} x^{3} + 6 \, {\left (b^{4} c^{3} d - a^{3} b d^{4}\right )} x^{2} - 12 \, {\left (b^{4} c^{4} - a^{4} d^{4}\right )} x}{b^{4} d^{4}}\right )} B b^{4} g^{4} + A a^{4} g^{4} x \]

input
integrate((b*g*x+a*g)^4*(A+B*log(e*(d*x+c)^2/(b*x+a)^2)),x, algorithm="max 
ima")
 
output
1/5*A*b^4*g^4*x^5 + A*a*b^3*g^4*x^4 + 2*A*a^2*b^2*g^4*x^3 + 2*A*a^3*b*g^4* 
x^2 + (x*log(d^2*e*x^2/(b^2*x^2 + 2*a*b*x + a^2) + 2*c*d*e*x/(b^2*x^2 + 2* 
a*b*x + a^2) + c^2*e/(b^2*x^2 + 2*a*b*x + a^2)) - 2*a*log(b*x + a)/b + 2*c 
*log(d*x + c)/d)*B*a^4*g^4 + 2*(x^2*log(d^2*e*x^2/(b^2*x^2 + 2*a*b*x + a^2 
) + 2*c*d*e*x/(b^2*x^2 + 2*a*b*x + a^2) + c^2*e/(b^2*x^2 + 2*a*b*x + a^2)) 
 + 2*a^2*log(b*x + a)/b^2 - 2*c^2*log(d*x + c)/d^2 + 2*(b*c - a*d)*x/(b*d) 
)*B*a^3*b*g^4 + 2*(x^3*log(d^2*e*x^2/(b^2*x^2 + 2*a*b*x + a^2) + 2*c*d*e*x 
/(b^2*x^2 + 2*a*b*x + a^2) + c^2*e/(b^2*x^2 + 2*a*b*x + a^2)) - 2*a^3*log( 
b*x + a)/b^3 + 2*c^3*log(d*x + c)/d^3 + ((b^2*c*d - a*b*d^2)*x^2 - 2*(b^2* 
c^2 - a^2*d^2)*x)/(b^2*d^2))*B*a^2*b^2*g^4 + 1/3*(3*x^4*log(d^2*e*x^2/(b^2 
*x^2 + 2*a*b*x + a^2) + 2*c*d*e*x/(b^2*x^2 + 2*a*b*x + a^2) + c^2*e/(b^2*x 
^2 + 2*a*b*x + a^2)) + 6*a^4*log(b*x + a)/b^4 - 6*c^4*log(d*x + c)/d^4 + ( 
2*(b^3*c*d^2 - a*b^2*d^3)*x^3 - 3*(b^3*c^2*d - a^2*b*d^3)*x^2 + 6*(b^3*c^3 
 - a^3*d^3)*x)/(b^3*d^3))*B*a*b^3*g^4 + 1/30*(6*x^5*log(d^2*e*x^2/(b^2*x^2 
 + 2*a*b*x + a^2) + 2*c*d*e*x/(b^2*x^2 + 2*a*b*x + a^2) + c^2*e/(b^2*x^2 + 
 2*a*b*x + a^2)) - 12*a^5*log(b*x + a)/b^5 + 12*c^5*log(d*x + c)/d^5 + (3* 
(b^4*c*d^3 - a*b^3*d^4)*x^4 - 4*(b^4*c^2*d^2 - a^2*b^2*d^4)*x^3 + 6*(b^4*c 
^3*d - a^3*b*d^4)*x^2 - 12*(b^4*c^4 - a^4*d^4)*x)/(b^4*d^4))*B*b^4*g^4 + A 
*a^4*g^4*x
 
3.3.1.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 487 vs. \(2 (170) = 340\).

Time = 63.43 (sec) , antiderivative size = 487, normalized size of antiderivative = 2.68 \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )\right ) \, dx=\frac {1}{5} \, A b^{4} g^{4} x^{5} - \frac {2 \, B a^{5} g^{4} \log \left (b x + a\right )}{5 \, b} + \frac {{\left (B b^{4} c g^{4} + 10 \, A a b^{3} d g^{4} - B a b^{3} d g^{4}\right )} x^{4}}{10 \, d} - \frac {2 \, {\left (B b^{4} c^{2} g^{4} - 5 \, B a b^{3} c d g^{4} - 15 \, A a^{2} b^{2} d^{2} g^{4} + 4 \, B a^{2} b^{2} d^{2} g^{4}\right )} x^{3}}{15 \, d^{2}} + \frac {1}{5} \, {\left (B b^{4} g^{4} x^{5} + 5 \, B a b^{3} g^{4} x^{4} + 10 \, B a^{2} b^{2} g^{4} x^{3} + 10 \, B a^{3} b g^{4} x^{2} + 5 \, B a^{4} g^{4} x\right )} \log \left (\frac {d^{2} e x^{2} + 2 \, c d e x + c^{2} e}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right ) + \frac {{\left (B b^{4} c^{3} g^{4} - 5 \, B a b^{3} c^{2} d g^{4} + 10 \, B a^{2} b^{2} c d^{2} g^{4} + 10 \, A a^{3} b d^{3} g^{4} - 6 \, B a^{3} b d^{3} g^{4}\right )} x^{2}}{5 \, d^{3}} - \frac {{\left (2 \, B b^{4} c^{4} g^{4} - 10 \, B a b^{3} c^{3} d g^{4} + 20 \, B a^{2} b^{2} c^{2} d^{2} g^{4} - 20 \, B a^{3} b c d^{3} g^{4} - 5 \, A a^{4} d^{4} g^{4} + 8 \, B a^{4} d^{4} g^{4}\right )} x}{5 \, d^{4}} + \frac {2 \, {\left (B b^{4} c^{5} g^{4} - 5 \, B a b^{3} c^{4} d g^{4} + 10 \, B a^{2} b^{2} c^{3} d^{2} g^{4} - 10 \, B a^{3} b c^{2} d^{3} g^{4} + 5 \, B a^{4} c d^{4} g^{4}\right )} \log \left (d x + c\right )}{5 \, d^{5}} \]

input
integrate((b*g*x+a*g)^4*(A+B*log(e*(d*x+c)^2/(b*x+a)^2)),x, algorithm="gia 
c")
 
output
1/5*A*b^4*g^4*x^5 - 2/5*B*a^5*g^4*log(b*x + a)/b + 1/10*(B*b^4*c*g^4 + 10* 
A*a*b^3*d*g^4 - B*a*b^3*d*g^4)*x^4/d - 2/15*(B*b^4*c^2*g^4 - 5*B*a*b^3*c*d 
*g^4 - 15*A*a^2*b^2*d^2*g^4 + 4*B*a^2*b^2*d^2*g^4)*x^3/d^2 + 1/5*(B*b^4*g^ 
4*x^5 + 5*B*a*b^3*g^4*x^4 + 10*B*a^2*b^2*g^4*x^3 + 10*B*a^3*b*g^4*x^2 + 5* 
B*a^4*g^4*x)*log((d^2*e*x^2 + 2*c*d*e*x + c^2*e)/(b^2*x^2 + 2*a*b*x + a^2) 
) + 1/5*(B*b^4*c^3*g^4 - 5*B*a*b^3*c^2*d*g^4 + 10*B*a^2*b^2*c*d^2*g^4 + 10 
*A*a^3*b*d^3*g^4 - 6*B*a^3*b*d^3*g^4)*x^2/d^3 - 1/5*(2*B*b^4*c^4*g^4 - 10* 
B*a*b^3*c^3*d*g^4 + 20*B*a^2*b^2*c^2*d^2*g^4 - 20*B*a^3*b*c*d^3*g^4 - 5*A* 
a^4*d^4*g^4 + 8*B*a^4*d^4*g^4)*x/d^4 + 2/5*(B*b^4*c^5*g^4 - 5*B*a*b^3*c^4* 
d*g^4 + 10*B*a^2*b^2*c^3*d^2*g^4 - 10*B*a^3*b*c^2*d^3*g^4 + 5*B*a^4*c*d^4* 
g^4)*log(d*x + c)/d^5
 
3.3.1.9 Mupad [B] (verification not implemented)

Time = 1.69 (sec) , antiderivative size = 1024, normalized size of antiderivative = 5.63 \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )\right ) \, dx=x^2\,\left (\frac {\left (5\,a\,d+5\,b\,c\right )\,\left (\frac {\left (\frac {b^3\,g^4\,\left (25\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{5\,d}-\frac {A\,b^3\,g^4\,\left (5\,a\,d+5\,b\,c\right )}{5\,d}\right )\,\left (5\,a\,d+5\,b\,c\right )}{5\,b\,d}-\frac {a\,b^2\,g^4\,\left (10\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{d}+\frac {A\,a\,b^3\,c\,g^4}{d}\right )}{10\,b\,d}+\frac {a^2\,b\,g^4\,\left (5\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{d}-\frac {a\,c\,\left (\frac {b^3\,g^4\,\left (25\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{5\,d}-\frac {A\,b^3\,g^4\,\left (5\,a\,d+5\,b\,c\right )}{5\,d}\right )}{2\,b\,d}\right )-x^3\,\left (\frac {\left (\frac {b^3\,g^4\,\left (25\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{5\,d}-\frac {A\,b^3\,g^4\,\left (5\,a\,d+5\,b\,c\right )}{5\,d}\right )\,\left (5\,a\,d+5\,b\,c\right )}{15\,b\,d}-\frac {a\,b^2\,g^4\,\left (10\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{3\,d}+\frac {A\,a\,b^3\,c\,g^4}{3\,d}\right )+x\,\left (\frac {a^3\,g^4\,\left (5\,A\,a\,d+10\,A\,b\,c-4\,B\,a\,d+4\,B\,b\,c\right )}{d}-\frac {\left (5\,a\,d+5\,b\,c\right )\,\left (\frac {\left (5\,a\,d+5\,b\,c\right )\,\left (\frac {\left (\frac {b^3\,g^4\,\left (25\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{5\,d}-\frac {A\,b^3\,g^4\,\left (5\,a\,d+5\,b\,c\right )}{5\,d}\right )\,\left (5\,a\,d+5\,b\,c\right )}{5\,b\,d}-\frac {a\,b^2\,g^4\,\left (10\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{d}+\frac {A\,a\,b^3\,c\,g^4}{d}\right )}{5\,b\,d}+\frac {2\,a^2\,b\,g^4\,\left (5\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{d}-\frac {a\,c\,\left (\frac {b^3\,g^4\,\left (25\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{5\,d}-\frac {A\,b^3\,g^4\,\left (5\,a\,d+5\,b\,c\right )}{5\,d}\right )}{b\,d}\right )}{5\,b\,d}+\frac {a\,c\,\left (\frac {\left (\frac {b^3\,g^4\,\left (25\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{5\,d}-\frac {A\,b^3\,g^4\,\left (5\,a\,d+5\,b\,c\right )}{5\,d}\right )\,\left (5\,a\,d+5\,b\,c\right )}{5\,b\,d}-\frac {a\,b^2\,g^4\,\left (10\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{d}+\frac {A\,a\,b^3\,c\,g^4}{d}\right )}{b\,d}\right )+\ln \left (\frac {e\,{\left (c+d\,x\right )}^2}{{\left (a+b\,x\right )}^2}\right )\,\left (B\,a^4\,g^4\,x+2\,B\,a^3\,b\,g^4\,x^2+2\,B\,a^2\,b^2\,g^4\,x^3+B\,a\,b^3\,g^4\,x^4+\frac {B\,b^4\,g^4\,x^5}{5}\right )+x^4\,\left (\frac {b^3\,g^4\,\left (25\,A\,a\,d+5\,A\,b\,c-2\,B\,a\,d+2\,B\,b\,c\right )}{20\,d}-\frac {A\,b^3\,g^4\,\left (5\,a\,d+5\,b\,c\right )}{20\,d}\right )+\frac {\ln \left (c+d\,x\right )\,\left (2\,B\,a^4\,c\,d^4\,g^4-4\,B\,a^3\,b\,c^2\,d^3\,g^4+4\,B\,a^2\,b^2\,c^3\,d^2\,g^4-2\,B\,a\,b^3\,c^4\,d\,g^4+\frac {2\,B\,b^4\,c^5\,g^4}{5}\right )}{d^5}+\frac {A\,b^4\,g^4\,x^5}{5}-\frac {2\,B\,a^5\,g^4\,\ln \left (a+b\,x\right )}{5\,b} \]

input
int((a*g + b*g*x)^4*(A + B*log((e*(c + d*x)^2)/(a + b*x)^2)),x)
 
output
x^2*(((5*a*d + 5*b*c)*((((b^3*g^4*(25*A*a*d + 5*A*b*c - 2*B*a*d + 2*B*b*c) 
)/(5*d) - (A*b^3*g^4*(5*a*d + 5*b*c))/(5*d))*(5*a*d + 5*b*c))/(5*b*d) - (a 
*b^2*g^4*(10*A*a*d + 5*A*b*c - 2*B*a*d + 2*B*b*c))/d + (A*a*b^3*c*g^4)/d)) 
/(10*b*d) + (a^2*b*g^4*(5*A*a*d + 5*A*b*c - 2*B*a*d + 2*B*b*c))/d - (a*c*( 
(b^3*g^4*(25*A*a*d + 5*A*b*c - 2*B*a*d + 2*B*b*c))/(5*d) - (A*b^3*g^4*(5*a 
*d + 5*b*c))/(5*d)))/(2*b*d)) - x^3*((((b^3*g^4*(25*A*a*d + 5*A*b*c - 2*B* 
a*d + 2*B*b*c))/(5*d) - (A*b^3*g^4*(5*a*d + 5*b*c))/(5*d))*(5*a*d + 5*b*c) 
)/(15*b*d) - (a*b^2*g^4*(10*A*a*d + 5*A*b*c - 2*B*a*d + 2*B*b*c))/(3*d) + 
(A*a*b^3*c*g^4)/(3*d)) + x*((a^3*g^4*(5*A*a*d + 10*A*b*c - 4*B*a*d + 4*B*b 
*c))/d - ((5*a*d + 5*b*c)*(((5*a*d + 5*b*c)*((((b^3*g^4*(25*A*a*d + 5*A*b* 
c - 2*B*a*d + 2*B*b*c))/(5*d) - (A*b^3*g^4*(5*a*d + 5*b*c))/(5*d))*(5*a*d 
+ 5*b*c))/(5*b*d) - (a*b^2*g^4*(10*A*a*d + 5*A*b*c - 2*B*a*d + 2*B*b*c))/d 
 + (A*a*b^3*c*g^4)/d))/(5*b*d) + (2*a^2*b*g^4*(5*A*a*d + 5*A*b*c - 2*B*a*d 
 + 2*B*b*c))/d - (a*c*((b^3*g^4*(25*A*a*d + 5*A*b*c - 2*B*a*d + 2*B*b*c))/ 
(5*d) - (A*b^3*g^4*(5*a*d + 5*b*c))/(5*d)))/(b*d)))/(5*b*d) + (a*c*((((b^3 
*g^4*(25*A*a*d + 5*A*b*c - 2*B*a*d + 2*B*b*c))/(5*d) - (A*b^3*g^4*(5*a*d + 
 5*b*c))/(5*d))*(5*a*d + 5*b*c))/(5*b*d) - (a*b^2*g^4*(10*A*a*d + 5*A*b*c 
- 2*B*a*d + 2*B*b*c))/d + (A*a*b^3*c*g^4)/d))/(b*d)) + log((e*(c + d*x)^2) 
/(a + b*x)^2)*((B*b^4*g^4*x^5)/5 + B*a^4*g^4*x + 2*B*a^3*b*g^4*x^2 + B*a*b 
^3*g^4*x^4 + 2*B*a^2*b^2*g^4*x^3) + x^4*((b^3*g^4*(25*A*a*d + 5*A*b*c -...